N2 + 3H2 --> 2NH3
how many grams of ammonia are made if you have 15.00 g of both N2 and H2 present?
Well, you have to figure the amount of moles of each you have.
molesN2=15/28
molesH2=15/2
so you have molN2=.538
and you must have three times that H3, or 1.61 moles. Well, you have too much H2, so all doesn't react.
moles ammonia you get is then 2*.538, convert that to grams.
To find out how many grams of ammonia are produced in the given reaction, we need to use stoichiometry.
Stoichiometry is a calculation method that relates the amount of reactants and products in a chemical equation.
In this case, the balanced chemical equation for the reaction is:
N2 + 3H2 --> 2NH3
This means that for every 1 mole of N2, 3 moles of H2, and 2 moles of NH3 are involved in the reaction.
To calculate the number of moles of N2 and H2, we can use their molar masses:
Molar mass of N2 = 14.01 g/mol (2 * 14.01 = 28.02 g/mol)
Molar mass of H2 = 2.02 g/mol (2 * 2.02 = 4.04 g/mol)
So, for the given 15.00 g of N2 and H2, we can calculate the number of moles using the formula:
Number of moles = Mass / Molar mass
Number of moles of N2 = 15.00 g / 28.02 g/mol = 0.535 mol
Number of moles of H2 = 15.00 g / 4.04 g/mol = 3.713 mol
Now, we need to determine the limiting reactant, which is the reactant that is not in excess and will be completely consumed. To do this, we compare the ratios of moles of N2 to H2. From the balanced equation, we can see that the ratio is 1:3.
The limiting reactant is the reactant with the smaller number of moles. In this case, N2 has 0.535 mol and H2 has 3.713 mol. Since N2 has fewer moles, it is the limiting reactant.
Now, we can use the stoichiometry of the balanced equation to calculate the moles of NH3 produced.
From the balanced equation, we know that the ratio of moles of N2 to moles of NH3 is 1:2.
So, the number of moles of NH3 produced can be calculated as:
Moles of NH3 = Moles of N2 * (2 moles of NH3 / 1 mole of N2)
= 0.535 mol * (2 mol NH3 / 1 mol N2)
= 1.07 mol NH3
Finally, we can calculate the mass of NH3 using the molar mass of NH3:
Molar mass of NH3 = 17.03 g/mol
Mass of NH3 = Moles of NH3 * Molar mass of NH3
= 1.07 mol * 17.03 g/mol
= 18.28 g
Therefore, the mass of ammonia produced when you have 15.00 g of both N2 and H2 present is 18.28 grams.