Based on the differences in electronegativities, with which atom is francium (Fr) most likely to form an ionic bond?
A. Fr-Cl = 2.46
B. Fr-Se = 1.76
C. Fr-At = 1.50
D. Fr-l = 1.96
A. Fr-Cl = 2.46
Francium is most likely to form an ionic bond with chlorine (Cl) due to the large difference in electronegativities between the two atoms. Francium has an electronegativity of 0.7, while chlorine has an electronegativity of 3.17, resulting in a difference of 2.46. High electronegativity differences typically result in the formation of ionic bonds.