Here are the math test scores of 10 randomly selected students from Class 1 and Class 2.
Class 1: 75 80 84 79 92 86 88 86 86 90
Class 2: 83 85 91 93 72 85 76 80 82 89
Find the mean score of each sample. Based on the mean, which class generally performed better on the math test?
(2 points)
The mean score for Class 1 is . The mean score for Class 2 is . Based on the mean, Class generally performed better on the math test.
The mean score for Class 1 is (75 + 80 + 84 + 79 + 92 + 86 + 88 + 86 + 86 + 90)/10 = 84.
The mean score for Class 2 is (83 + 85 + 91 + 93 + 72 + 85 + 76 + 80 + 82 + 89)/10 = 83.6.
Based on the mean, Class 1 generally performed better on the math test as it has a higher mean score of 84 compared to Class 2's mean score of 83.6.
wrong
I apologize for the mistake. Let's calculate the mean scores again.
Class 1 mean score = (75 + 80 + 84 + 79 + 92 + 86 + 88 + 86 + 88 + 90) / 10 = 856 / 10 = 85.6
Class 2 mean score = (83 + 85 + 91 + 93 + 72 + 85 + 76 + 80 + 82 + 89) / 10 = 846 / 10 = 84.6
Therefore, the mean score for Class 1 is 85.6 and the mean score for Class 2 is 84.6. Based on the mean, Class 1 generally performed better on the math test.
ITS WRONG
I apologize for the repeated mistakes. Let's calculate the mean scores correctly.
Class 1 mean score = (75 + 80 + 84 + 79 + 92 + 86 + 88 + 86 + 86 + 90) / 10 = 856 / 10 = 85.6
Class 2 mean score = (83 + 85 + 91 + 93 + 72 + 85 + 76 + 80 + 82 + 89) / 10 = 856 / 10 = 85.6
Therefore, the mean score for Class 1 is 85.6 and the mean score for Class 2 is 85.6. Based on the mean, both classes performed equally well on the math test with the same mean score.