The data shows the number of miles run per week by randomly selected students from two different classes. Find the difference between the medians. Which class has a higher median? By how much? Class 1: 6, 8, 10, 11, 14, 4, 5, 8, 2, 7, 7, 5, 10, 12, 11 Class 2: 6, 4, 5, 6, 7, 8, 12, 9, 10, 11, 5, 8, 7, 4, 10
Comparing data distributions qc:
1. cats because the range of their weights is less
2. 1 pound
3. class 1 has a higher median by 1 mile
4. Fertilizer b is generally more effective, because the mean and median weights of the potatoes that were treated with it are higher.
5. The swimming club has a greater spread than the swimming club. The hiking club is symmetrical, and the swimming club is skewed left. The hiking club has a peak at 5. The swimming club has a peak at 9 and 10.
You are correct. I apologize for the oversight. Let's recalculate the medians for both classes.
For Class 1: 2, 4, 5, 5, 6, 7, 7, 8, 8, 10, 10, 11, 11, 12, 14
The median is the middle value, which is the 8th value in the list: 8
For Class 2: 4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 9, 10, 10, 11, 12
The median is the middle value, which is the 7th value in the list: 7
The difference between the medians is 8 - 7 = 1 mile. Therefore, Class 1 has a higher median than Class 2 by 1 mile.
To find the medians for each class, we first need to arrange the data in ascending order.
For Class 1: 2, 4, 5, 5, 6, 7, 7, 8, 8, 10, 10, 11, 11, 12, 14
Median: (8 + 8) / 2 = 8
For Class 2: 4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 9, 10, 10, 11, 12
Median: (7 + 8) / 2 = 7.5
The difference between the medians is 8 - 7.5 = 0.5. Therefore, Class 1 has a higher median than Class 2 by 0.5 miles.
wrong
I apologize for the mistake in my previous response. Let's find the correct median for each class.
For Class 1: 2, 4, 5, 5, 6, 7, 7, 8, 8, 10, 10, 11, 11, 12, 14
The median is the middle value, which is the 8th value in the list: 8
For Class 2: 4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 9, 10, 10, 11, 12
The median is the average of the middle two values, which are the 8th and 9th values: (8 + 8) / 2 = 8
The difference between the medians is 8 - 8 = 0. Therefore, both Class 1 and Class 2 have the same median of 8 miles per week.
wrong again just find the median of both classes then find the difference
Let's find the medians for both classes again and then calculate the difference:
Class 1: 2, 4, 5, 5, 6, 7, 7, 8, 8, 10, 10, 11, 11, 12, 14
The median is the middle value, which is the 8th value in the list: 8
Class 2: 4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 9, 10, 10, 11, 12
The median is the middle value, which is the 8th value in the list: 8
The difference between the medians is 8 - 8 = 0. Therefore, both Class 1 and Class 2 have the same median of 8 miles per week.
the median for class 2 is 7
Thank you for the comparisons and analysis. Let me know if you need further assistance.
Comparing Data Distributions Quick Check
4 of 54 of 5 Items
Question
The data shows the number of seconds it took two randomly selected groups to thread a needle. Compare the measures of center and variability of these data sets.
Student Group A: 56, 14, 26, 28, 29, 45, 32, 80, 3, 10
Student Group B: 27, 24, 18, 19, 5, 16, 22, 10, 6, 20
Which of the following statements about these data sets is false?
(1 point)
Responses
The amount of variability of the time taken by Group A to thread a needle is higher than the amount of variability of the time taken by Group B.
The amount of variability of the time taken by Group A to thread a needle is higher than the amount of variability of the time taken by Group B.
The mean time taken by Group A is higher than that of Group B.
The mean time taken by Group A is higher than that of Group B.
The median time taken by members of Group A to thread a needle is higher than that of members of Group B.
The median time taken by members of Group A to thread a needle is higher than that of members of Group B.
The ranges of the time taken by Group A and Group B are the same.