Solve using the quadratic formula.
9t^2 + 6t + 1 = 0
Write your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.
t=____ or t=____
To solve the equation 9t^2 + 6t + 1 = 0 using the quadratic formula, we first identify the coefficients a = 9, b = 6, and c = 1.
The quadratic formula is given by:
t = (-b ± √(b^2 - 4ac)) / 2a
Substitute the values of a, b, and c into the formula:
t = (-6 ± √(6^2 - 4*9*1)) / (2*9)
t = (-6 ± √(36 - 36)) / 18
t = (-6 ± √0) / 18
t = -6 / 18
t = -1/3
Therefore, the solutions are:
t = -1/3 or t = -1/3