Solve using the quadratic formula write your answers as integers proper or improper fractions in simplest form or decimals rounded to the nearest hundredth
4x^2-6x+2=0
To solve the quadratic equation 4x^2 - 6x + 2 = 0 using the quadratic formula, first identify the coefficients a, b, and c in the general quadratic equation ax^2 + bx + c = 0.
In this case, a = 4, b = -6, and c = 2.
Now, substitute the values of a, b, and c into the quadratic formula:
x = [ -(-6) ± √((-6)^2 - 4(4)(2)) ] / 2(4)
x = [ 6 ± √(36 - 32) ] / 8
x = [ 6 ± √4 ] / 8
x = [ 6 ± 2 ] / 8
This gives two possible solutions:
x = (6 + 2) / 8 = 8 / 8 = 1
x = (6 - 2) / 8 = 4 / 8 = 1/2
Therefore, the solutions to the quadratic equation 4x^2 - 6x + 2 = 0 are x = 1 and x = 1/2.