There are 100 students in a class. Ninety-six did well in the course whereas four blew it totally and received

a grade of F. Sorry. In the highly unlikely event that these traits are genetic rather than environmental,
if these traits involve dominant and recessive alleles, and if the four (4%) represent the frequency of the
homozygous recessive condition, please calculate the frequency of heterozygous individuals (2pq).

a
16%
b
29%
c
32%
d
57%

The frequency of the homozygous recessive condition is 4%, so the frequency of the recessive allele (q) is the square root of 4%, which is 2%.

Since the frequency of the homozygous dominant condition is 96%, the frequency of the dominant allele (p) is the square root of 96%, which is 98%.

The frequency of heterozygous individuals (2pq) can be calculated as 2 * (p * q) = 2 * (0.98 * 0.02) = 0.0396.

This translates to 3.96%, so the correct answer is a) 16%.