1)Write equations showing how sodium oxide and zinc oxide are formed
2)i)Write equations to show how the following react with water;
a)Na
b)Al
c)Zn
d)Fe
e)Cu
ii)From the above equations,write down the reactivity series
3)Explain why copper remains unreactive with water
4)Using equations show how the following metals react with hydrochloric acid;
a)Na
b)All
c)Fe
d)Zn
e)Cu
5)Using equations show how the following metals react with chlorine gas(green yellow gas);
a)Na
b)All
c)Fe
d)Zn
e)Cu
6)Using equations show how the following metals (Na,Al,Fe,Cu,Zn)react with dilute sulphuric acid and;
a)Sate the colour of solution formed
b)State whether soluble or insoluble
1)
Sodium oxide: 2Na + 1/2O2 -> Na2O
Zinc oxide: 2Zn + O2 -> 2ZnO
2) i)
a) 2Na + 2H2O -> 2NaOH + H2
b) 2Al + 6H2O -> 2Al(OH)3 + 3H2
c) Zn + 2H2O -> Zn(OH)2 + H2
d) Fe + 2H2O -> Fe(OH)2 + H2
e) Cu + 2H2O -> No reaction
ii) Reactivity series:
Na > Al > Zn > Fe > Cu
3) Copper remains unreactive with water because it is less reactive than water, it does not displace hydrogen from water to form a metal hydroxide and hydrogen gas.
4)
a) 2Na + 2HCl -> 2NaCl + H2
b) 2Al + 6HCl -> 2AlCl3 + 3H2
c) Fe + 2HCl -> FeCl2 + H2
d) Zn + 2HCl -> ZnCl2 + H2
e) Cu + 2HCl -> No reaction
5)
a) 2Na + Cl2 -> 2NaCl
b) 2Al + 3Cl2 -> 2AlCl3
c) Fe + Cl2 -> FeCl3
d) Zn + Cl2 -> ZnCl2
e) Cu + Cl2 -> No reaction
6)
a)
Na + H2SO4 -> Na2SO4 + H2 (colourless solution)
Al + H2SO4 -> Al2(SO4)3 + H2 (colourless solution)
Fe + H2SO4 -> FeSO4 + H2 (green solution)
Cu + H2SO4 -> CuSO4 + H2 (blue solution)
Zn + H2SO4 -> ZnSO4 + H2 (colourless solution)
b)
All the metal sulfates formed are soluble.