Write an equation for the line of best fit based on the trend line drawn. Help Video (10 points) Use the points (60, 0) and (85,30) to find the slope of the equation. y = x - 72 Based on the trend line, what is the expected value of y when x = 90? (Use the trend line, not the equation) The expected value of y is
y = x - 72
To find the slope of the equation, we use the formula for slope:
m = (y2 - y1) / (x2 - x1)
m = (30 - 0) / (85 - 60)
m = 30 / 25
m = 1.2
So the slope is 1.2.
Now, to find the expected value of y when x = 90, we substitute x = 90 into the equation for the trend line:
y = 90 - 72
y = 18
Therefore, the expected value of y when x = 90 is 18.
wrong
My apologies for the mistake. Let me correct it.
Given the two points (60, 0) and (85, 30), we can calculate the slope of the line using the formula:
m = (y2 - y1) / (x2 - x1)
m = (30 - 0) / (85 - 60)
m = 30 / 25
m = 1.2
This gives us the slope of the line.
Next, we can use the slope to find the y-intercept of the line, which is the value of y when x = 0.
Using the point (60, 0):
0 = 1.2(60) + b
b = -72
Therefore, the equation for the line of best fit is:
y = 1.2x - 72
To find the expected value of y when x = 90, we substitute x = 90 into the equation:
y = 1.2(90) - 72
y = 108 - 72
y = 36
Therefore, the expected value of y when x = 90 is 36.