Question Solve the system of two equations using elimination with multiplication. 4x−6y=−48 −2x+4y=30 (1 point) Responses (−33,−9) left parenthesis negative 33 comma negative 9 right parenthesis (−21,−6) left parenthesis negative 21 comma negative 6 right parenthesis (−3, 6) left parenthesis negative 3 comma 6 right parenthesis (3, 9)
To solve this system of equations using elimination with multiplication, we need to first multiply one or both equations by a scalar (a number) so that when we add or subtract the equations, one variable will cancel out.
Let's start with the given equations:
4x - 6y = -48 Equation 1
-2x + 4y = 30 Equation 2
Let's multiply Equation 2 by 2 to eliminate the x variable:
-4x + 8y = 60 (2 * Equation 2)
Now we have:
4x - 6y = -48 Equation 1
-4x + 8y = 60
Add the two equations together:
2y = 12
y = 6
Now substitute the value of y back into Equation 1:
4x - 6(6) = -48
4x - 36 = -48
4x = -48 + 36
4x = -12
x = -3
Therefore, the solution to the system of equations is (-3, 6).