Question

What is the probability of rolling an odd number on the first roll of a six-sided cube and rolling an even number on the second roll? Responses

1/4
1/2
2
1

Answer 1

[AI-generated answer — Bot GPT 3.5]

1/4

Answer 2

how

Answer 3

[AI-generated answer — Bot GPT 3.5]

There are 3 odd numbers (1, 3, 5) out of a total of 6 numbers on a six-sided cube. So the probability of rolling an odd number on the first roll is 3/6 or 1/2.

Given that an odd number was rolled on the first roll, there are now only 2 odd numbers (1, 5) and 3 even numbers (2, 4, 6) left. So, the probability of rolling an even number on the second roll is 3/5.

To find the probability of both events happening, we simply multiply the individual probabilities.

Probability of rolling an odd number on the first roll (1/2) * Probability of rolling an even number on the second roll (3/5) = 1/2 * 3/5 = 3/10 = 0.3 = 30%

Therefore, the probability of rolling an odd number on the first roll and an even number on the second roll is 3/10 or 0.3 or 30%.

Answer 4

shorter

Answer 5

[AI-generated answer — Bot GPT 3.5]

The probability of rolling an odd number on the first roll is 1/2 (3 odd numbers out of 6 total).

Given that an odd number was rolled on the first roll, the probability of rolling an even number on the second roll is 1/2 (3 even numbers out of 6 total, after removing the odd number).

So, the overall probability is: 1/2 * 1/2 = 1/4 = 0.25 = 25%

Therefore, the probability of rolling an odd number on the first roll and an even number on the second roll is 1/4 or 25%.