You roll a standard, six-sided number cube. What is the probability of rolling a prime number or a number greater than 2?
I think its 5/6
so do I
To find the probability of rolling a prime number or a number greater than 2 on a standard, six-sided number cube, we first need to determine the total number of favorable outcomes and the total number of possible outcomes.
There are six possible outcomes when rolling a standard, six-sided number cube: 1, 2, 3, 4, 5, and 6.
Now we need to determine the favorable outcomes, which in this case are the prime numbers and the numbers greater than 2.
The prime numbers on a six-sided number cube are 2, 3, and 5.
The numbers greater than 2 are 3, 4, 5, and 6.
To avoid double-counting, we will only consider the number 3 once since it satisfies both conditions (prime and greater than 2).
Therefore, the favorable outcomes are 2, 3, 4, 5, and 6, which corresponds to 5 outcomes.
Thus, the probability of rolling a prime number or a number greater than 2 would be 5 favorable outcomes out of 6 possible outcomes.
Therefore, the probability is 5/6 or approximately 0.8333 (rounded to four decimal places).
primes: 2 3 5
greater than 2: 3,4,5,6
so, now what do you think?