Consider the graph that represents the following quadratic equation.
y=-1/3(x+2)^2+5
The graph opens upward or downward
The vertex of the graph is (2,5), (-2,-5) or (-2,5)
The axis of symmetry of the graph is x=2 or x=-2
The graph opens upward because the coefficient of the x^2 term is negative.
The vertex of the graph is (-2,5). This can be found by comparing the equation y = -1/3(x + 2)^2 + 5 to the standard form y = a(x - h)^2 + k. In this case, h = -2 and k = 5, giving us the vertex (-2, 5).
The axis of symmetry of the graph is x = -2. This can be determined by identifying the x-coordinate of the vertex.