Given the equation y=x2−16x+89 with zeros of x=8−5i and x=8+5i , which of the following identifies the general shape of its associated graph?(1 point)
Responses
The graph opens downward.
The graph opens downward.
The vertex is to the left of the y-axis.
The vertex is to the left of the y -axis.
The graph lies above the x-axis.
The graph lies above the x -axis.
The graph touches the x-axis exactly twice.
Given the equation y=x2−16x+89 with zeros of x=8−5i and x=8+5i , which of the following identifies the general shape of its associated graph?(1 point)
Responses
The graph opens downward.
The graph opens downward.
The vertex is to the left of the y-axis.
The vertex is to the left of the y -axis.
The graph lies above the x-axis.
The graph lies above the x -axis.
The graph touches the x-axis exactly twice.
To identify the general shape of the graph associated with the given equation, you can examine the leading coefficient of the quadratic term, which is the coefficient of x^2. In this case, the leading coefficient is 1.
If the leading coefficient is positive (greater than 0), the graph opens upward, and if the leading coefficient is negative (less than 0), the graph opens downward.
In the given equation, since the leading coefficient is positive (1), the graph opens upward.
Therefore, the correct response is: The graph opens upward.
The correct response is:
The graph opens upward.
The correct response is:
The graph opens upward.