Elements A and B react according to the following balanced equation.
3A2+2B → 2A3B
The molar mass of element A is 4g/mol. The molar mass of element B is 16g/mol. When the initial mass of element A is 48g, which mass of element B should be present?
(1 point)
Responses
96g
96g
64g
64g
128g
128g
192g
192g
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The correct answer is 64g.
To solve for the mass of element B, we first need to determine the moles of element A present:
Moles of A = Mass of A / Molar mass of A
Moles of A = 48g / 4g/mol
Moles of A = 12 mol
According to the balanced equation, the ratio of moles of A to moles of B is 3:2. Therefore, we can determine the moles of B by using this ratio:
Moles of B = (12 mol * 2) / 3
Moles of B = 8 mol
Now we can calculate the mass of element B:
Mass of B = Moles of B * Molar mass of B
Mass of B = 8 mol * 16g/mol
Mass of B = 128g
Therefore, the correct mass of element B that should be present is 64g.