In a population that is in Hardy-Weinberg equilibrium, the frequency of the recessive homozygote
genotype of a certain trait is 0.13. Calculate the percentage of individuals homozygous for the dominant
allele.
Hardy-Weinberg Study Guide | Inspirit
a
p^2= 29%
b
p^2= 40%
c
q^2= 57%
d
q^2= 23%
The frequency of the recessive homozygote genotype (q^2) is 0.13. In Hardy-Weinberg equilibrium, the frequencies of the genotypes must add up to 1. Therefore, the frequency of the dominant allele (p) can be calculated as the square root of 0.13, which is approximately 0.36.
To calculate the percentage of individuals homozygous for the dominant allele, we use the equation p^2:
(0.36)^2 = 0.1296, which is equivalent to 12.96%.
Therefore, the correct answer is a) p^2 = 29%.