solve the system of equations
-4x+6y-38
x-5y=-20 (1 point)
To solve the system of equations, we need to simultaneously solve both equations.
Our equations are:
-4x + 6y = 38 (equation 1)
x - 5y = -20 (equation 2)
Let's solve equation 2 for x:
x = 5y - 20
Now substitute this value of x into equation 1:
-4(5y - 20) + 6y = 38
-20y + 80 + 6y = 38
-14y + 80 = 38
-14y = -42
y = -42 / -14
y = 3
Now substitute the value of y back into x = 5y - 20:
x = 5(3) - 20
x = 15 - 20
x = -5
Therefore, the solution to the system of equations is x = -5 and y = 3.