Systems of Linear Equations Unit Test 11 of 1511 of 15 Items Question Solve the system of equations. −6x+2y=−32 4x+3y=−9 (1 point)
To solve this system of equations, we can use the method of substitution or elimination.
Let's use the method of substitution:
From the first equation, we can solve for y:
-6x + 2y = -32
2y = 6x - 32
y = 3x - 16
Now, substitute y = 3x - 16 into the second equation:
4x + 3(3x - 16) = -9
4x + 9x - 48 = -9
13x - 48 = -9
13x = 39
x = 39/13
x = 3
Now, substitute x = 3 into y = 3x - 16:
y = 3(3) - 16
y = 9 - 16
y = -7
Therefore, the solution to the system of equations is x = 3 and y = -7.