Solve the equation x^2+2x−48=0 . Show your work to receive all the points. You can use the photo icon to upload a picture of your work or use the E symbol for math symbols. (3 points)
To solve the quadratic equation x^2 + 2x - 48 = 0, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / 2a
In this equation, a = 1, b = 2, and c = -48. Plugging these values into the formula, we get:
x = (-2 ± √(2^2 - 4*1*(-48))) / 2*1
x = (-2 ± √(4 + 192)) / 2
x = (-2 ± √196) / 2
x = (-2 ± 14) / 2
Now we have two possible solutions:
x = (-2 + 14) / 2 = 12 / 2 = 6
x = (-2 - 14) / 2 = -16 / 2 = -8
So the solutions to the equation x^2 + 2x - 48 = 0 are x = 6 and x = -8.