Solve the following equation. You must show all work to receive full credit. aa2−25+2a+5=2a−5
To solve the equation, we first need to simplify the left side of the equation:
aa2 - 25 + 2a + 5 = 2a - 5
a^3 - 25 + 2a + 5 = 2a - 5
a^3 + 2a - 20 = 2a - 5
Next, we can subtract 2a on both sides of the equation to isolate the variable:
a^3 + 2a - 2a - 20 = 2a - 2a - 5
a^3 - 20 = -5
Now, we can add 20 to both sides of the equation to solve for a^3:
a^3 = -5 + 20
a^3 = 15
Finally, we can take the cube root of both sides to solve for a:
a = ∛15
Therefore, the solution to the equation is a = ∛15.