Two cards are drawn without replacement from a standard deck of 52
playing cards. What is the probability of choosing a king and then, without replacement, another king? Express your answer as a fraction or a decimal number rounded to four decimal places.
There are a total of 52 cards in a standard deck, and 4 of them are kings.
The probability of choosing a king on the first draw is 4/52 = 1/13.
Since the first king has already been drawn, there are now only 51 cards left in the deck, and only 3 kings remaining.
Therefore, the probability of choosing another king on the second draw is 3/51 = 1/17.
To find the probability of both events happening, we multiply the individual probabilities:
(1/13) * (1/17) = 1/221 ≈ 0.0045
Therefore, the probability of choosing a king and then, without replacement, another king is approximately 0.0045.