A standard deck of 52 cards contains four suits: hearts, diamonds, clubs, and spades. Each suit has 13 cards: ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, and king. Two cards are randomly drawn without replacement. Calculate the probability of drawing two diamond cards. Express your answer in percent form rounding to the nearest hundredth.(1 point)
There are 13 diamond cards in the deck, so the probability of drawing the first diamond card is 13/52 = 1/4.
After drawing one diamond card, there are 12 diamond cards left in the deck and the total number of remaining cards is now only 51.
Therefore, the probability of drawing a second diamond card after already drawing one is 12/51.
To find the probability of drawing two diamond cards, we multiply the probabilities of drawing each card: (1/4) * (12/51) = 3/51.
Converting 3/51 to a decimal gives 0.0588.
Multiplying by 100 to convert to percentage form, we get 5.88%.
Therefore, the probability of drawing two diamond cards without replacement is approximately 5.88%.
round it out to the nearest hundredth
Rounding 5.88% to the nearest hundredth gives us 5.88%.
Therefore, the probability of drawing two diamond cards without replacement is 5.88%.