Question 1
There are four presidential candidates in a country. A street survey was conducted asking 2,500 registered voters which candidate they will vote for in the coming election. The table summarizes the results of the survey.
Presidential Candidates Number of Supporters
Candidate 1 250
Candidate 2 1,250
Candidate 3 450
Candidate 4 550
250+1,250+450+550=2,500 so candidate 2 has more supporters
a. What is the probability of randomly selecting a person who will vote for Candidate 1 or 2?
90%. I rewrote 0.9 as a percentage
90/100=90%
b. If 1,000 more voters are surveyed, how many of them will likely prefer Candidate 3 or 4? Explain the answer and show work.
Question 2
A basket of fruits contains 20 apples, 4 watermelon slices, and 12 oranges. If a piece of fruit is to be selected randomly from the box, what is the probability of selecting an apple or an orange? Explain as a simplified fraction
a. To find the probability of selecting a person who will vote for Candidate 3 or 4, we need to first calculate the total number of supporters for Candidate 3 and 4 in the initial survey.
Candidate 3: 450 supporters
Candidate 4: 550 supporters
Total supporters for Candidate 3 and 4: 450 + 550 = 1,000 supporters
If 1,000 more voters are surveyed, it is expected that the proportion of voters supporting each candidate will remain the same. Therefore, out of the additional 1,000 surveyed voters, 450 will likely support Candidate 3 and 550 will likely support Candidate 4.
Therefore, out of the additional 1,000 surveyed voters, 450 + 550 = 1,000 voters will likely prefer Candidate 3 or 4.
b. The probability of selecting an apple or an orange can be calculated as follows:
Total number of apples: 20
Total number of oranges: 12
Total number of fruits: 20 + 4 + 12 = 36
Probability of selecting an apple or an orange = (Number of apples + Number of oranges) / Total number of fruits
= (20 + 12) / 36
= 32 / 36
= 8 / 9
Therefore, the probability of selecting an apple or an orange is 8/9.