Use the image to answer the question.
A coordinate plane of 4 quadrants shows x and y axes ranging from negative 3 to 3 in increments of 1. A line with arrows at each end intercepts two plotted points, A and B. Point A is plotted at left parenthesis negative 1 comma 2 right parenthesis. Point B is plotted at left parenthesis 0 comma negative 1 right parenthesis.
Write the equation of the line in slope-intercept form.
(1 point)
y= ___x+(___)
To find the equation of the line in slope-intercept form, we need to find the slope (m) and the y-intercept (b).
First, let's find the slope (m) using the two points A and B:
m = (y2 - y1) / (x2 - x1)
m = (-1 - 2) / (0 - (-1))
m = (-3) / (1)
m = -3
Now, we know the slope (m) is -3. Next, we can find the y-intercept (b) by substituting one of the points (A or B) into the equation y = mx + b. Let's use point A (-1, 2):
2 = (-3)(-1) + b
2 = 3 + b
b = -1
Now we have found the slope (m = -3) and the y-intercept (b = -1), so we can write the equation of the line in slope-intercept form:
y = -3x - 1
So, the equation of the line in slope-intercept form is:
y = -3x - 1
Its not subtraction
Apologies for the error. Let's correct the equation:
The slope is already determined as -3.
Using one of the points (A or B) to find the y-intercept:
Let's use point A (-1, 2):
y = mx + b
2 = -3(-1) + b
2 = 3 + b
b = -1
Therefore, the correct equation of the line in slope-intercept form is:
y = -3x - 1