Consider the graph of the following quadratic equation: y=x^2+4x-5. What is the axis of symmetry?

The axis of symmetry for the graph of the quadratic equation y=x^2+4x-5 is x=-2. This is because the axis of symmetry for a parabola in the form y=ax^2+bx+c is given by x=-b/(2a). In this case, a=1 and b=4, so x=-4/(2*1) = -2.