Use the image to answer the question.
There are four adjoining rectangles of the same height positioned so their vertical sides touch. The first and third rectangles from the left are the same size as each other. The second and fourth rectangles from the left are also the same size as each other but wider than the first and third. The first rectangle is labeled 7 centimeters on the left side and 2 centimeters on the bottom side. The fourth rectangle is labeled 10 centimeters on the bottom side. The second rectangle has identical small rectangles touching its top and bottom sides. The small rectangles are the same width as the second rectangle.
The net of a rectangular prism is shown. What is the surface area of the rectangular prism?
(1 point)
Responses
138 cm.2
138 cm.2
208 cm.2
208 cm.2
306 cm.2
306 cm.2
104 cm.2
104 cm.2
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To find the surface area of the rectangular prism, we need to find the area of each face and then add them up.
First, we have the front and back faces, which are both 7 cm by 2 cm. Each face has an area of 7 cm x 2 cm = 14 cm^2.
Next, we have the top and bottom faces. The top face is 10 cm by 2 cm (same as the width of the rectangle). The bottom face is also 10 cm by 2 cm. Each of these faces has an area of 10 cm x 2 cm = 20 cm^2.
Finally, we have the left and right faces. The left face is 7 cm by 10 cm, and the right face is also 7 cm by 10 cm. Each of these faces has an area of 7 cm x 10 cm = 70 cm^2.
Now, we add up all the areas:
Front and back: 14 cm^2 + 14 cm^2 = 28 cm^2
Top and bottom: 20 cm^2 + 20 cm^2 = 40 cm^2
Left and right: 70 cm^2 + 70 cm^2 = 140 cm^2
Total surface area = 28 cm^2 + 40 cm^2 + 140 cm^2 = 208 cm^2
Therefore, the surface area of the rectangular prism is 208 cm^2.
The correct answer is: 208 cm^2