Use the image to answer the question.
There are four adjoining rectangles of the same height positioned so their vertical sides touch. The first and third rectangles from the left are the same size as each other. The second and fourth rectangles from the left are also the same size as each other but wider than the first and third. The first rectangle is labeled 7 centimeters on the left side and 2 centimeters on the bottom side. The fourth rectangle is labeled 10 centimeters on the bottom side. The second rectangle has identical small rectangles touching its top and bottom sides. The small rectangles are the same width as the second rectangle.
The net of a rectangular prism is shown. What is the surface area of the rectangular prism?
(1 point)
Responses
104 cm.2104 cm.2
306 cm.2306 cm.2
208 cm.2208 cm.2
138 cm.2138 cm.2
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To find the surface area of the rectangular prism, we need to find the area of each individual rectangle and then add them up.
1st rectangle:
Top side: 7 cm * 2 cm = 14 cm^2
Front side: 7 cm * 10 cm = 70 cm^2
Side 1: 2 cm * 10 cm = 20 cm^2
Total area of the first rectangle: 14 cm^2 + 70 cm^2 + 20 cm^2 = 104 cm^2
2nd rectangle:
Top side: 7 cm * 10 cm = 70 cm^2
Front side: 10 cm * 10 cm = 100 cm^2
Side 1: 2 cm * 10 cm = 20 cm^2
Side 2: 2 cm * 10 cm = 20 cm^2
Total area of the second rectangle: 70 cm^2 + 100 cm^2 + 20 cm^2 + 20 cm^2 = 210 cm^2
3rd rectangle:
This is the same size as the first rectangle.
Total area of the third rectangle: 104 cm^2
4th rectangle:
This is the same size as the second rectangle.
Total area of the fourth rectangle: 210 cm^2
Now we add up all the areas:
104 cm^2 + 210 cm^2 + 104 cm^2 + 210 cm^2 = 628 cm^2
Therefore, the surface area of the rectangular prism is 628 cm^2.