Jessica is making a chocolate milkshake in a blender. A tiny, .0050 kg chocolate chip is rapidly spun around the inside of the container with a speed of 14 m/s, held by a centripetal force of 10 N. What is the radius of the blender at this location? (show your solution
First, we need to find the centripetal force acting on the chocolate chip:
F = m*v^2 / r
Where:
F = centripetal force (10 N)
m = mass of the chocolate chip (0.0050 kg)
v = speed of the chocolate chip (14 m/s)
r = radius of the blender
Plugging in the values:
10 = 0.0050 * 14^2 / r
10 = 0.0050 * 196 / r
10 = 0.98 / r
r = 0.098 m
Therefore, the radius of the blender at this location is 0.098 meters.