A negative charge of 3 * 10c experiences a force of 0.12N when in an electric field. What is the magnitude of the field intensity? You must show all work in the appropriate spaces on the form for full credit.
Equation Used
Assign value to the variable
Show Your Work
Answer with Units
The equation used is:
F = qE
Where:
F = force = 0.12N
q = charge = -3 * 10^-6C
E = electric field intensity (what we're solving for)
Plugging in the values:
0.12N = -3 * 10^-6C * E
Solving for E:
E = 0.12N / -3 * 10^-6C
E = -0.04 * 10^6 N/C
E = -40,000 N/C
Therefore, the magnitude of the electric field intensity is 40,000 N/C.