A negative charge of 3 x 10-4 C experiences a force of 0.12N when in an electric field. What is the magnitude of the field intensity? Show your work and answer with correct units.
Equation used
Show your work
Answer with units
F = qE
0.12N = (3 x 10-4 C)E
E = 0.12N / (3 x 10-4 C)
E = 4 x 104 N/C
Answer: The magnitude of the field intensity is 4 x 104 N/C.
To find the magnitude of the electric field intensity, we can use the equation F = qE, where F is the force experienced by the charge q in an electric field with intensity E.
Given:
Charge (q) = -3 x 10^(-4) C (Negative charge)
Force (F) = 0.12 N
Rearranging the equation, we have E = F / q.
Substituting the given values, we get:
E = 0.12 N / (-3 x 10^(-4) C) = -0.4 x 10^4 N/C.
Therefore, the magnitude of the electric field intensity is 0.4 x 10^4 N/C (Note: Magnitude is always positive, so we ignore the negative sign).
Answer: The magnitude of the electric field intensity is 0.4 x 10^4 N/C.