3d base
2 base
1 base
If it is 90 feet between bases, how far is it from home base to 2nd base?
(1 point)
○ 90²+b²=90²; 127.3 ft
○ 90² +90² = c²; 19 ft
○ 90²+90²=c²; 180 ft
○ 90²+90²= c²; 127.3 ft
○ 90² + 90² = c²
○ 8100 + 8100 = c²
○ 16200 = c²
○ c = √16200
○ c ≈ 127.3 ft
Therefore, it is approximately 127.3 feet from home base to 2nd base.