Step by step bot answer this please Ashortstop is standing in the base path between second base and third base when she fields the ball she is 34 feet from the second base and needs to make the throw to first base. Assuming the field is square, how far does she need to throw the ball round your answer to the nearest 10th there are 3 bases and she is right next tot eh second one and the base 2 and 3 are 35 feet and 1st and second are 90 It’s a right triangle and it’s not 96.1
To solve this problem, we can use the Pythagorean theorem to find the distance she needs to throw the ball.
Let's label the bases:
- Second base (where the shortstop is standing) = B2
- Third base = B3
- First base = B1
From the given information, we know:
- Distance between B2 and B3 = 35 feet
- Distance between B1 and B2 = 90 feet
We need to find the distance between B2 and B1, which is the throw the shortstop needs to make.
Using the Pythagorean theorem (a² + b² = c²), where a and b are the legs of a right triangle and c is the hypotenuse, we have:
a = 34 feet
b = 35 feet
c = ?
Let's substitute the values into the equation and solve for c:
34² + 35² = c²
1156 + 1225 = c²
2381 = c²
To find c, we take the square root of both sides of the equation:
c = √2381 ≈ 48.8 feet
Therefore, the shortstop needs to throw the ball approximately 48.8 feet to first base.