Luke rode his bicycle 2/5 mile from his house to the library then he rode one half mile from the library to the mall how far from Luke's house could the mall be how close could it be explain your reasoning and draw a diagram to support your answer

To find the maximum and minimum distance from Luke's house to the mall, we have to consider the total distance Luke traveled from his house to the mall.

From the information given, Luke rode 2/5 mile from his house to the library and then half a mile from the library to the mall. So the total distance he rode is:

2/5 + 1/2 = 4/10 + 5/10 = 9/10 mile

Therefore, the maximum distance the mall could be from Luke's house is 9/10 mile away. This would happen if the library was exactly in between Luke's house and the mall.

The minimum distance the mall could be from Luke's house is 7/10 mile away. This would happen if the library and the mall were almost directly next to each other, closer to Luke's house.

Here is a diagram to support this answer:

House --(2/5 miles)--> Library --(1/2 mile)--> Mall

In this diagram, the distance from his house to the library is 2/5 mile and the distance from the library to the mall is 1/2 mile. The total distance from his house to the mall is 9/10 mile.