3= 10x^2 + 13x
To solve for x, we need to isolate the variable x.
3 = 10x^2 + 13x
Rearrange the equation to set it equal to 0:
10x^2 + 13x - 3 = 0
Now we have a quadratic equation in the form ax^2 + bx + c = 0, where a = 10, b = 13, and c = -3.
To solve for x, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / 2a
Plugging in the values of a, b, and c:
x = (-13 ± √(13^2 - 4*10*-3)) / 2*10
x = (-13 ± √(169 + 120)) / 20
x = (-13 ± √289) / 20
x = (-13 ± 17) / 20
Now we have two possible solutions for x:
x1 = (-13 + 17) / 20
x1 = 4 / 20
x1 = 1/5
x2 = (-13 - 17) / 20
x2 = -30 / 20
x2 = -3/2
Therefore, the solutions for x are x = 1/5 and x = -3/2.