3= 10x^2 + 13x

To solve for x, we need to isolate the variable x.

3 = 10x^2 + 13x

Rearrange the equation to set it equal to 0:

10x^2 + 13x - 3 = 0

Now we have a quadratic equation in the form ax^2 + bx + c = 0, where a = 10, b = 13, and c = -3.

To solve for x, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / 2a

Plugging in the values of a, b, and c:

x = (-13 ± √(13^2 - 4*10*-3)) / 2*10
x = (-13 ± √(169 + 120)) / 20
x = (-13 ± √289) / 20
x = (-13 ± 17) / 20

Now we have two possible solutions for x:

x1 = (-13 + 17) / 20
x1 = 4 / 20
x1 = 1/5

x2 = (-13 - 17) / 20
x2 = -30 / 20
x2 = -3/2

Therefore, the solutions for x are x = 1/5 and x = -3/2.