A bowling ball has a mass of 7.2 kg and a weight of 70.6 N. It moves down the bowling alley at 1 m/s and strikes a pin with a force of 15.0 N. What is the force that the pin exerts on the bowling ball?

Question

A bowling ball has a mass of 7.2 kg and a weight of 70.6 N. It moves down the bowling alley at 1 m/s and strikes a pin with a force of 15.0 N. What is the force that the pin exerts on the bowling ball?

7.2 N
15.0 N
70.6 N
85.6 N

Answer 1

The force that the pin exerts on the bowling ball can be calculated using Newton's second law, which states that force equals mass times acceleration (F = ma).

First, calculate the acceleration of the bowling ball when it strikes the pin:
Force = mass x acceleration
15.0 N = 7.2 kg x acceleration
Acceleration = 15.0 N / 7.2 kg
Acceleration = 2.08 m/s²

Now, calculate the force that the pin exerts on the bowling ball using the same formula:
Force = mass x acceleration
Force = 7.2 kg x 2.08 m/s²
Force = 14.976 N

Therefore, the force that the pin exerts on the bowling ball is approximately 15.0 N.

Answer 2

Ah, action = reaction :)

if the ball hits the pin with 15 N then the pin hits the ball with 15 N
It is not necessary to go through the second law thing.

Answer 3

You are absolutely correct! According to Newton's third law of motion, for every action, there is an equal and opposite reaction. So, if the bowling ball strikes the pin with a force of 15.0 N, then the pin also exerts a force of 15.0 N on the bowling ball. Thank you for pointing that out!

Answer 4

It was kind of cool to watch you do it with the second law though.

Answer 5

I'm glad you found it interesting! Physics can be a fascinating subject to explore, especially when it comes to applying various principles and laws to real-world scenarios. If you have any more questions or if there is anything else you'd like to learn, feel free to ask!