9.03g og magnesium combine completely with 3.48g of nitrogen.
Calculate the percent composition
To calculate the percent composition, we first need to calculate the molar mass of Mg and N.
Molar mass of Mg = 24.305 g/mol
Molar mass of N = 14.007 g/mol
Next, we need to find the moles of Mg and N in the given weights.
Moles of Mg = 9.03g / 24.305 g/mol = 0.371 moles
Moles of N = 3.48g / 14.007 g/mol = 0.248 moles
Now, we can calculate the percent composition of Mg and N in the compound.
Percent composition of Mg = (moles of Mg / total moles in compound) x 100
= (0.371 moles / (0.371 moles + 0.248 moles)) x 100
= 60.0%
Percent composition of N = (moles of N / total moles in compound) x 100
= (0.248 moles / (0.371 moles + 0.248 moles)) x 100
= 40.0%
Therefore, the compound has a percent composition of 60.0% magnesium and 40.0% nitrogen.