29.0g Ag combine completely with 4.30g S to form a compound. what is the percent composition of each element in this compound
Percent Compound is:
(Amount of Element)
-------------------------------(100)
(Total Molecule Mass)
Total mass: 29+4.3 = 33.3g
Sulfur: (4.3/33.3)100 = 12.9%.
Silver: (29/33.3)100 = 87.1%.
the chemical formula
Well, when Ag and S got together, they said, "Let's form a compound!" Ag being the go-getter that it is, decided to combine completely with 4.30g of S.
To find the percent composition, we need to determine the mass of each element in the compound.
First, let's find the mass of Ag in the compound. Since Ag combined completely, we can assume that the mass of Ag in the compound is equal to the mass of Ag added. So, the mass of Ag is 29.0g.
Next, let's find the mass of S in the compound. Similarly, since S combined completely, the mass of S in the compound is equal to the mass of S added. So, the mass of S is 4.30g.
To calculate the percent composition of each element, we divide the mass of each element by the total mass of the compound and multiply by 100.
For Ag:
Percent Ag = (mass of Ag / total mass of compound) × 100
Percent Ag = (29.0g / (29.0g + 4.30g)) × 100
For S:
Percent S = (mass of S / total mass of compound) × 100
Percent S = (4.30g / (29.0g + 4.30g)) × 100
Now, to the calculations:
Percent Ag = (29.0g / 33.30g) × 100
Percent Ag ≈ 87.4%
Percent S = (4.30g / 33.30g) × 100
Percent S ≈ 12.9%
So, the percent composition of Ag in this compound is approximately 87.4%, and the percent composition of S is approximately 12.9%.
To find the percent composition of each element in the compound, we need to determine the molar mass of Ag and S. The molar mass of Ag is 107.87 g/mol, and the molar mass of S is 32.06 g/mol.
Next, we need to calculate the number of moles of each element present in the compound. We can use the formula:
moles = mass / molar mass
For Ag:
moles of Ag = 29.0 g / 107.87 g/mol = 0.269 mol
For S:
moles of S = 4.30 g / 32.06 g/mol = 0.134 mol
Now, let's calculate the percent composition of each element:
Percent composition of Ag = (moles of Ag / total moles in compound) * 100
= (0.269 mol / (0.269 mol + 0.134 mol)) * 100
= 66.7%
Percent composition of S = (moles of S / total moles in compound) * 100
= (0.134 mol / (0.269 mol + 0.134 mol)) * 100
= 33.3%
Therefore, the percent composition of Ag in the compound is 66.7% and the percent composition of S is 33.3%.
To find the percent composition of each element in the compound formed by the combination of Ag and S, you need to calculate the mass of each element in the compound and then find the percentage.
Step 1: Calculate the mass of Ag in the compound.
Given: Mass of Ag = 29.0g
Since Ag combines completely with S, the entire mass of Ag is present in the compound.
Step 2: Calculate the mass of S in the compound.
Given: Mass of S = 4.30g
Since S combines completely with Ag, the entire mass of S is also present in the compound.
Step 3: Calculate the total mass of the compound.
The total mass of the compound is the sum of the masses of Ag and S.
Total mass = Mass of Ag + Mass of S
Step 4: Calculate the percent composition of each element.
Percent composition of Ag = (Mass of Ag / Total mass) * 100
Percent composition of S = (Mass of S / Total mass) * 100
Let's plug in the values to calculate the percent composition:
Total mass = 29.0g + 4.30g = 33.30g
Percent composition of Ag = (29.0g / 33.30g) * 100
= 87.11%
Percent composition of S = (4.30g / 33.30g) * 100
= 12.89%
Therefore, the percent composition of each element in the compound is as follows:
Ag: 87.11%
S: 12.89%