A bakery owner wants to ensure they make enough cookies each day to meet the demand from customers. On average, they sell 92 cookies a day with a standard deviation of 9. The baker makes 70 cookies each day. Using a calculator or a spreadsheet program, find the probability that the baker made enough cookies (no more than 70 cookies sold that day). Round the answer to the nearest tenth of a percent.(1 point)
To find the probability that the baker made enough cookies (no more than 70 sold), we need to calculate the z-score first.
Z = (X - μ) / σ
Z = (70 - 92) / 9
Z = -2.44
Next, we look up the z-score in a standard normal distribution table or use a calculator to find the corresponding probability:
P(Z < -2.44) ≈ 0.0073
Therefore, the probability that the baker made enough cookies is approximately 0.73%, rounded to the nearest tenth of a percent.