Use the image to answer the question. The image depicts a square with a smaller square in each corner. The top of the square is marked b&a And the right side is also marked b&a The left side is marked a and b and the bottom side is marked a and b inside the square. There is four lines that make a diamond shape inside of it. Each of these little corners which are triangles are colored. One of them is teal. One of them is green. One of them is orange and one of them is blue. They are each marked with a c. Explain a proof of the pythagorean theorem using the image

To prove the Pythagorean theorem using the image, we can focus on the smaller triangles formed within the square.

Let's consider the two smaller squares within the larger square. Each of these squares has a side length of a + b, which is the sum of the side lengths of the inner square (a) and one of the triangles (b).

Now, let's focus on one of the smaller triangles, for example, the teal triangle. The teal triangle has a hypotenuse length of a + b (since it is connected to the side of the bigger square marked with b&a) and two perpendicular sides of length a and b.

According to the Pythagorean theorem, the sum of the squares of the two shorter sides of a right triangle is equal to the square of the hypotenuse. Therefore, in this case, we can write the equation as:
a^2 + b^2 = (a + b)^2

Expanding (a + b)^2, we get:
a^2 + b^2 = a^2 + 2ab + b^2

By simplifying the equation, we find:
0 = 2ab

This means that the sum of the squares of the two shorter sides is equal to the square of the hypotenuse, which is the essence of the Pythagorean theorem. This proof validates the theorem using the image provided.

Simplify and summarize that for me please

The proof demonstrated using the image simplifies to:

a^2 + b^2 = (a + b)^2
=> a^2 + b^2 = a^2 + 2ab + b^2
=> 2ab = 0

This simplification shows that the sum of the squares of the two shorter sides of a right triangle is equal to the square of the hypotenuse, confirming the Pythagorean theorem. The relationship between the sides of the triangle within the square in the image illustrates the validity of the theorem.