Vehicle 1 Mass = 1,500 kg Velocity = 15 m/
Calculate the amount of force acting on Vehicle 1 if it crashes into a bus and it takes 0.01 seconds for Vehicle 1 to come to a stop upon collision. a. Step 1: Calculate the acceleration of the vehicle as its velocity changes from 15 to 0 m/s in 0.01 seconds. b. Step 2: Apply Newton’s Second Law of Motion to determine the force exerted by the vehicle on the bus during the crash. c. Step 3: Apply Newton’s Third Law of Motion to determine the force exerted by the wall on the vehicle. d. Step 4: Calculate the acceleration of the bus given its mass is 2,000 kg. e. Step 5: After the collision, will the velocity be increasing, decreasing, or constant? Why?
a. Step 1:
The acceleration of the vehicle can be calculated using the formula: acceleration = (final velocity - initial velocity) / time
acceleration = (0 - 15) / 0.01
acceleration = -1500 m/s^2
b. Step 2:
To determine the force exerted by the vehicle on the bus, we can use Newton's Second Law of Motion:
Force = mass x acceleration
Force = 1500 kg x -1500 m/s^2
Force = -2,250,000 N
c. Step 3:
According to Newton's Third Law of Motion, the force exerted by the wall on the vehicle will be equal in magnitude but opposite in direction to the force exerted by the vehicle on the wall. Therefore, the force exerted by the wall on the vehicle will also be 2,250,000 N.
d. Step 4:
To calculate the acceleration of the bus, we can use the formula: acceleration = force / mass
acceleration = 2,250,000 N / 2000 kg
acceleration = 1125 m/s^2
e. Step 5:
After the collision, the velocity of both the vehicle and the bus will be decreasing because the force exerted by the vehicle on the bus and the force exerted by the bus on the vehicle are in opposite directions, causing them to slow down.