If the wavelength is increased to 10m while the speed remains at 600 m/s, the frequency of the wave would decrease to 60 Hz. This is because frequency and wavelength are inversely proportional to each other when speed is held constant.
The formula for the relationship between frequency, wavelength, and speed is:
\(v = f \times \lambda\)
Where:
\(v\) = speed of the wave
\(f\) = frequency of the wave
\(\lambda\) = wavelength of the wave
If the speed remains constant at 600 m/s and the wavelength is increased to 10m, we can rearrange the formula to solve for the new frequency:
\(f = v / \lambda\)
Plugging in the values, we get:
\(f = 600 / 10\)
\(f = 60\)
Therefore, the frequency of the wave would decrease to 60 Hz if the wavelength is increased to 10m while the speed remains at 600 m/s.