What is the surface area of the rectangular pyramid and on the front base? It’s 8 mm on the left the arrows pointing to align that is in the middle of the pyramid and it’s 12 and ends and on the right side. There’s a line going down the middle that is 10 MM and then also on the right side there’s another arrow pointing to the middle and it’s 15 MM, so what is the surface area of the rectangular pyramid?
To find the surface area of the rectangular pyramid, we need to calculate the area of the base and the area of the three triangular faces.
The front base of the pyramid is a rectangle with dimensions 8mm x 12mm, so the area of the base is 8mm x 12mm = 96mm^2.
Next, we need to calculate the area of the three triangular faces. Two of the triangular faces have base 8mm and height 10mm, so their area is (1/2) x base x height = (1/2) x 8mm x 10mm = 40mm^2 each.
The third triangular face has base 12mm and height 15mm, so its area is (1/2) x 12mm x 15mm = 90mm^2.
Therefore, the total surface area of the rectangular pyramid is 96mm^2 (base area) + 40mm^2 + 40mm^2 + 90mm^2 = 266mm^2.