what is the net ionic equation of the reaction of ZnCl2 with NaOH?
The reaction of ZnCl2 with NaOH can be written as:
ZnCl2 + 2NaOH -> Zn(OH)2 + 2NaCl
The net ionic equation for this reaction is:
Zn^2+ (aq) + 2OH^- (aq) -> Zn(OH)2 (s)
ZnCl2 + 2NaOH -> Zn(OH)2 + 2NaCl
The net ionic equation for this reaction is:
Zn^2+ (aq) + 2OH^- (aq) -> Zn(OH)2 (s)