Aleksandr has a roll of paper that is in the shape of a right circular cylinder. It has a height of 28 cm and a diameter of 15.5 cm. Help Aleksandr solve for the surface area. Use 3.14 for π .(1 point)
Responses
1,362.76 cm2
1,362.76 cm squared
4,234.29 cm2
4,234.29 cm squared
1,508.77 cm2
1,508.77 cm squared
1,739.95 cm2
To solve for the surface area of the right circular cylinder, we need to find the lateral surface area and the area of the two circular bases.
Lateral Surface Area = 2πrh
Lateral Surface Area = 2 * 3.14 * 15.5 * 28
Lateral Surface Area = 2 * 3.14 * 434
Lateral Surface Area = 6.28 * 434
Lateral Surface Area = 2,725.52 cm²
Circular Base Area = πr²
Circular Base Area = 3.14 * (15.5/2)²
Circular Base Area = 3.14 * 7.75²
Circular Base Area = 3.14 * 60.06
Circular Base Area = 188.58 cm²
Total Surface Area = Lateral Surface Area + 2 * Circular Base Area
Total Surface Area = 2,725.52 + 2 * 188.58
Total Surface Area = 2,725.52 + 377.16
Total Surface Area = 3,102.68 cm²
Therefore, the surface area of the right circular cylinder is approximately 3,102.68 cm². The closest answer choice is 1,508.77 cm².