use the image described to answer the question.
An illustration shows a horizontal rectangle of height 9 inches with a circle of radius 10 inches attached to its top left and a circle of radius 10 inches attached to its bottom right.
find the surface area of the net diagram of the right circular cylinder. Use 3.14 for π.
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To find the surface area of the net diagram of the right circular cylinder, we need to calculate the areas of the three rectangles (front, back, and side) and the two circles (top and bottom).
1. Front rectangle:
Height = 9 inches, Width = 20 inches
Area = Height x Width = 9 x 20 = 180 square inches
2. Back rectangle:
Height = 9 inches, Width = 20 inches
Area = Height x Width = 9 x 20 = 180 square inches
3. Side rectangle:
Height = 9 inches, Width = 10 inches
Area = Height x Width = 9 x 10 = 90 square inches
4. Top circle:
Radius = 10 inches
Area = πr^2 = 3.14 x 10^2 = 3.14 x 100 = 314 square inches
5. Bottom circle:
Radius = 10 inches
Area = πr^2 = 3.14 x 10^2 = 3.14 x 100 = 314 square inches
Now, add up the areas of all the components:
180 + 180 + 90 + 314 + 314 = 978 square inches
Therefore, the surface area of the net diagram of the right circular cylinder is 978 square inches.
not right
I apologize for the error in my previous response. Let's correct that.
To find the surface area of the net diagram of the right circular cylinder, we need to consider the following components:
1. Front rectangle:
Height = 9 inches, Width = 20 inches
Area = Height x Width = 9 x 20 = 180 square inches
2. Back rectangle:
This is the same as the front rectangle.
Area = 180 square inches
3. Side rectangle:
This rectangle wraps around the cylinder and has a length equal to the circumference of the circles.
Circumference of a circle = 2πr
Circumference = 2 x 3.14 x 10 inches = 62.8 inches
Height of the rectangle = 9 inches
Area = Height x Circumference = 9 x 62.8 ≈ 565.2 square inches
Adding up the areas of the three rectangles gives:
180 + 180 + 565.2 = 925.2 square inches
Therefore, the surface area of the net diagram of the right circular cylinder is approximately 925.2 square inches.
not right again
I apologize for the errors in my previous responses. Let's correct that again.
To find the surface area of the net diagram of the right circular cylinder, we need to consider the following components:
1. Front rectangle:
Height = 9 inches, Width = 20 inches
Area = Height x Width = 9 x 20 = 180 square inches
2. Back rectangle:
This is the same as the front rectangle.
Area = 180 square inches
3. Side rectangle:
This rectangle wraps around the cylinder and has a length equal to the height of the cylinder.
Height of the cylinder = 9 inches
Circumference of the circles = 2πr = 2 x 3.14 x 10 = 62.8 inches
Area = Height x Circumference = 9 x 62.8 = 565.2 square inches
Adding up the areas of the three rectangles gives:
180 + 180 + 565.2 = 925.2 square inches
Since the top and bottom circles are already included in the front and back rectangles, we do not add their areas separately.
Therefore, the surface area of the net diagram of the right circular cylinder is 925.2 square inches. Thank you for your patience.