Use the image to answer the question.

An illustration shows a rectangle that extends to a smaller rectangle at the bottom left. The length of the bottom rectangle is much lesser on the right. The dimensions are as follows: The larger rectangle shows the right side as 4, truncated bottom length as 3, and left side end to end as 5 including the extended rectangle. The smaller rectangle shows the bottom length as 2. There are 5 right angled symbols to show the perpendicular lines of the two rectangles.

What is the area of the composite figure in square units?(1 point)
square units

incorrect.

still not correct bro.

still not correct cmon

Wrong bot

To find the area of the composite figure, we need to calculate the area of each individual rectangle and then add them together.

The area of the larger rectangle is calculated by multiplying its length by its width. The length is given as 5, but since there is an extended rectangle on the bottom left, we need to subtract the length of the smaller rectangle (2) from it. So the length of the larger rectangle is 5 - 2 = 3. The width is given as 4.

Therefore, the area of the larger rectangle is 3 * 4 = 12 square units.

The area of the smaller rectangle is simply the product of its length and width, which are given as 2 and 3 respectively. Thus, the area of the smaller rectangle is 2 * 3 = 6 square units.

To find the total area of the composite figure, we add the areas of the larger and smaller rectangles together: 12 + 6 = 18 square units.

Therefore, the area of the composite figure is 18 square units.

Apologies for the mistake. Let's recalculate the area of the composite figure using the correct measurements.

The area of the larger rectangle can be found by multiplying its length by its width. The length of the larger rectangle is 5 units (including the extended rectangle) and the width is 4 units. So the area of the larger rectangle is 5 * 4 = 20 square units.

The area of the smaller rectangle can be found by multiplying its length by its width. The length of the smaller rectangle is 2 units and the width is 3 units. So the area of the smaller rectangle is 2 * 3 = 6 square units.

To find the total area of the composite figure, we add the areas of the larger and smaller rectangles together: 20 + 6 = 26 square units.

Therefore, the area of the composite figure is 26 square units.

Apologies for the mistake. Let's reevaluate the measurements and calculate the area of the composite figure accurately.

The larger rectangle has a length of 5 units (including the extended rectangle) and a width of 4 units. Therefore, the area of the larger rectangle is 5 * 4 = 20 square units.

The smaller rectangle has a length of 2 units and a width of 3 units. Thus, the area of the smaller rectangle is 2 * 3 = 6 square units.

To calculate the area of the composite figure, we need to subtract the overlapping area between the two rectangles. The overlapping area can be determined by subtracting the area of the smaller rectangle from the extended portion of the larger rectangle.

The extended portion of the larger rectangle can be calculated by subtracting the width of the smaller rectangle (3 units) from the total length of the larger rectangle (5 units). Therefore, the extended portion of the larger rectangle is 5 - 3 = 2 units.

The overlapping area is then the width of the smaller rectangle (3 units) multiplied by the extended portion of the larger rectangle (2 units). So, the overlapping area is 3 * 2 = 6 square units.

Finally, the area of the composite figure is the area of the larger rectangle (20 square units) minus the overlapping area (6 square units). Therefore, the area of the composite figure is 20 - 6 = 14 square units.