Surface area of a square pyramid is 160cm^2. The area of the lateral triangles is 96cm^2. What is length of one of the sides.
Let the base of the square pyramid be an x by x square, with height h.
Given that the lateral triangles have an area of 96cm^2, we can set up the equation as follows:
4 * (1/2) * x * s = 96
2x * s = 96
xs = 48
The total surface area of the square pyramid is 160cm^2, so we can set up another equation:
x^2 + 4 * (1/2) * x * s = 160
x^2 + 2xs = 160
x^2 + 2(48) = 160
x^2 = 160 - 96
x^2 = 64
x = 8cm
Therefore, the length of one side of the square base is 8cm.