What is the value of n such that the expression x² + 11x + n is a perfect square trinomial?
In order for the expression x² + 11x + n to be a perfect square trinomial, the coefficient of the linear term (11x) must be half of the coefficient of the middle term when squared.
So, we have:
n = (11/2)²
n = 121/4
n = 30.25
Therefore, the value of n is 30.25.