Graphing Linear Equations Unit Test
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Question
Use the image to answer the question.
An illustration of a coordinate plane with four quadrants shows the x-axis ranging from negative 9 to 9 and the y-axis ranging from negative 11 to 11 in increments of 1. A solid upward line with arrows at both ends is plotted on the graph. The line passes through the plotted points left parenthesis 0 comma negative 2 right parenthesis and left parenthesis 1 comma 3 right parenthesis.
Use the graph to derive the equation of the line in slope-intercept form.
(1 point)
The equation of the line in slope-intercept form is y = 5x - 2.
Explanation:
The slope of the line can be calculated using the formula:
m = (y2 - y1) / (x2 - x1)
Using the points (0, -2) and (1, 3), the slope can be calculated as:
m = (3 - (-2)) / (1 - 0)
m = 5 / 1
m = 5
Once the slope is determined, we can use one of the points to find the y-intercept. Plugging in (0, -2) into the equation y = mx + b, we can solve for b:
-2 = 5(0) + b
b = -2
Therefore, the equation of the line in slope-intercept form is y = 5x - 2.