Use the image to answer the question.
A coordinate plane of 4 quadrants shows x and y axes ranging from negative 3 to 3 in increments of 1. A line with arrows at each end intercepts two plotted points, A and B. Point A is plotted at left parenthesis negative 1 comma 2 right parenthesis. Point B is plotted at left parenthesis 0 comma negative 1 right parenthesis.
Write the equation of the line in slope-intercept form.
(1 point)
To find the equation of the line in slope-intercept form, we first need to determine the slope of the line using the two plotted points.
Slope (m) = (y2 - y1) / (x2 - x1)
Slope (m) = (-1 - 2) / (0 - (-1))
Slope (m) = -3 / 1
Slope (m) = -3
Next, we plug one of the points (let's use point A) and the slope into the slope-intercept form equation y = mx + b to solve for the y-intercept (b).
2 = -3(-1) + b
2 = 3 + b
b = -1
Now that we have the slope (m = -3) and the y-intercept (b = -1), we can write the equation of the line in slope-intercept form:
y = -3x - 1